Lake Alfred is a region located in FL, and has a population of 5,083. This region is policed by LAKE ALFRED POLICE DEPARTMENT.
Lake Alfred has an overall crime rate of 4,486 per 100,000 residents. This is moderately safer than the rest of the United States, but still about average. This means that your chances of becoming a victim of any type of crime in Lake Alfred is 1 in 22 if you reside there for a year.
The average overall crime rate for Lake Alfred for the previous 2 years was 3,394 per 100,000 residents. This means that the crime rate for Lake Alfred has been increasing over time.
Below are its crime rates and policing statistics according to the FBI's Uniform Crime Reports (UCR). For more specific crime statistics (NIBRS) for many US cities & counties, see Offense Statistics.
|Crime Rate (Overall)||4,486||4,506|
|Forced Entry Rate||393||417|
|Auto Theft Rate||98||362|
|Auto Theft Clearance||0%||12%|
Sex OffendersOf the 730,000 sex offenders in the United States, there are a total of 20 sex offender(s) in Lake Alfred. On a per capita basis, there are approximately 393 sex offender(s) per 100,000 people in Lake Alfred. This is compared to the nation-wide average of 240 sex offenders per 100,000 people.
To search the official state sex offender registry for Florida see http://offender.fdle.state.fl.us/offender/homepage.do
Data estimated from arrests & clearances from a sample from the Uniform Crime Reports, Federal Bureau of Investigation, U.S. Department of Justice. Washington, D.C. 2011. If missing data exist, these figures will tend to underestimate the true figures. Insideprison.com is not responsible for the currency or accuracy of this data.